Timeline for Generating a finite group from elements in each conjugacy class
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 22, 2020 at 2:17 | comment | added | LSpice | A follow-up question: math.stackexchange.com/q/3875776 . | |
| May 16, 2019 at 17:41 | history | edited | Hugo Chapdelaine | CC BY-SA 4.0 |
added 51 characters in body
|
| Oct 15, 2012 at 13:16 | history | edited | Hugo Chapdelaine | CC BY-SA 3.0 |
added 17 characters in body
|
| Oct 15, 2012 at 13:14 | comment | added | Hugo Chapdelaine | Hi Geoff, you are perfectly right, there is no reason to expect the two characters to be irreducible. | |
| Oct 15, 2012 at 0:50 | comment | added | Geoff Robinson | I do not think the last statement is correct. Take $G = A_{5}$ and $H$ to be a Sylow $5$-subgroup of $G.$ No two distinct irreducible characters of $G$ agree on $H.$ The only two irreducible characters which have equal degree are the two irreducible characters of degree $3$, and these do not agree on a $5$-cycle. | |
| May 2, 2012 at 23:22 | history | answered | Hugo Chapdelaine | CC BY-SA 3.0 |