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May 24, 2012 at 20:11 comment added Lubin I’ve never had occasion to do so in a publication, but what I use in my own notes is $A^{(p^{-1})}$.
May 24, 2012 at 16:27 history edited Karl Schwede
Fixed a tag
Apr 29, 2012 at 15:24 comment added Andrea Mori @Kevin Buzzard: I actually like the idea of calling it $A^{(1/p)}$! I'm sort of surprised, though, that there is no standard notation for it, like if this object had not been given much consideration.
Apr 29, 2012 at 13:07 comment added Kevin Buzzard Or perhaps you could call it $A^\sigma$ where $\sigma$ is the $p$th root map on the base.
Apr 29, 2012 at 13:06 comment added Kevin Buzzard I guess you could call it $A^{(1/p)}$? Of course $A^{(p)}$ makes sense over any scheme where $p=0$ but $A^{(1/p)}$ relies on your base being e.g. a perfect field, so it won't come up as much I guess.
Apr 29, 2012 at 11:42 history asked Andrea Mori CC BY-SA 3.0