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Feb 20, 2014 at 8:46 history edited user9072
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Aug 3, 2012 at 5:03 vote accept Adterram
Apr 27, 2012 at 18:38 comment added Mariano Suárez-Álvarez Todd: smoothly truncating $e^{-x^2}$ on $\mathbb R$ so as to obtain a sequence of compactly supported functions appropriately should give a Cauchy sequence in that metric which does not converge, no?
Apr 27, 2012 at 17:50 comment added Todd Leason Added: $K$ has to be taken to include the support of $f,g$.
Apr 27, 2012 at 17:46 comment added Todd Leason I don't know if this is usual, but it should be possible to define a metric by $$d(f,g) = \sum_n \frac{1}{2^{n+A(n)}}\sum_{|\alpha|=n}\frac{\left|\sup_K\frac\partial{\partial x^\alpha}(f-g)\right|}{1 + \left|\sup_K\frac\partial{\partial x^\alpha}(f-g)\right|}$$ where $A(n)$ is the number of $\alpha$ s.t. $|\alpha|=n$. The space should be complete in the induced topology.
Apr 27, 2012 at 17:28 answer added John Pardon timeline score: 24
Apr 27, 2012 at 16:29 comment added Zev Chonoles Crossposted to math.SE: math.stackexchange.com/q/137701/264
Apr 27, 2012 at 16:18 history asked Adterram CC BY-SA 3.0