Skip to main content
7 events
when toggle format what by license comment
May 2, 2012 at 3:49 comment added Mark.Neuhaus Ryan then I guess that you just didn't recognized that I didn't assumed the embedding to be closed. So the anser to my first question is no.
May 2, 2012 at 1:37 comment added Ryan Budney The Urysohn lemma requires the submanifold to be closed, so it's no contradiction.
May 2, 2012 at 0:38 comment added Mark.Neuhaus I'm a little confused because what Igor said seems to contradict what Ryan said since I do not assume that $i(M)$ is closed in $N$.
Apr 27, 2012 at 6:58 comment added Igor Khavkine For the surjectivity question and important condition is that the image of $M$ be closed in $N$. Otherwise, if $M$ has an end, smooth functions on $M$ could have wild behavior as they approach that end and not correspond to the restriction of any smooth function from the ambient manifold $N$. Think $(0,1)$ in $\mathbb{R}$.
Apr 26, 2012 at 21:21 vote accept Mark.Neuhaus
May 2, 2012 at 0:39
Apr 26, 2012 at 21:20 comment added Mark.Neuhaus ok. Didn't see that it was that easy. So I vote for close to, since I don't want to delete it, just in case someone else is looking for the same thing in future.
Apr 26, 2012 at 21:15 history answered Ryan Budney CC BY-SA 3.0