Timeline for ODE in symmetric definite positive matrices
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 25, 2012 at 21:59 | vote | accept | Bernard | ||
| Apr 25, 2012 at 21:38 | answer | added | Pietro Majer | timeline score: 7 | |
| Apr 25, 2012 at 21:20 | history | edited | Bernard | CC BY-SA 3.0 |
edited body
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| Apr 25, 2012 at 21:10 | comment | added | Bernard | sorry, it is indeed (2). To avoid confusion, t is a scalar and x is a positive matrix. When dimension is 1, everything goes well, when dimension is higher I'm not sure what can be done. | |
| Apr 25, 2012 at 21:08 | history | edited | Bernard | CC BY-SA 3.0 |
sorry, I got confused when typing my ODE, corrected this.
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| Apr 25, 2012 at 20:59 | comment | added | Aaron Hoffman | (1) Do you mean df/dx = 1/(a-bx^2)? Or perhaps df/dx = a-bf^2? (2) Is the matrix problem an ODE, i.e. is x a scalar? If so, why write xbx? | |
| Apr 25, 2012 at 20:56 | comment | added | Federico Poloni | Something is wrong with your scalar version of the ODE. As it is written, it suffices to integrate in $dx$ on both sides to get $f(x)=ax-\frac{b}3x^3+C$. Please correct the text. | |
| Apr 25, 2012 at 20:48 | comment | added | Steve Huntsman | Casual guess: some judicious combination of time/path-ordering (en.wikipedia.org/wiki/Ordered_exponential) and diagonalization might help. | |
| Apr 25, 2012 at 20:21 | history | asked | Bernard | CC BY-SA 3.0 |