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May 4, 2022 at 7:47 history edited Liviu Nicolaescu CC BY-SA 4.0
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Jul 9, 2012 at 12:45 vote accept TerronaBell
May 7, 2012 at 10:38 history edited Liviu Nicolaescu CC BY-SA 3.0
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May 2, 2012 at 20:32 comment added Liviu Nicolaescu @Robert: I screwed my comment above. You are right. I have updated my answer. In the book I cite, Hormander computes the an asymptotic expansion for the kernel of $(r+\delta)^{-1}$ for any $r>0$.
May 2, 2012 at 20:29 history edited Liviu Nicolaescu CC BY-SA 3.0
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May 2, 2012 at 20:22 comment added Liviu Nicolaescu @ Robert: Ooops! Thanks for point his out. $F_\nu$ does depend on $r$ In the definition of $F_\nu$ (|\xi|^2+1)$ needs to be replaced with $(|\xi|^2+r)$. The $U_\nu$'s will not depend on $r$. In fact Hormander's carries the computation for any $r$. I will edit my answer.
May 2, 2012 at 15:06 comment added Robert Bryant What happened to $S_r$, and why do the $F_\nu$ not depend on $r$ even though the recursion relations that they satisfy do depend on $r$?
May 2, 2012 at 9:49 history edited Liviu Nicolaescu CC BY-SA 3.0
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Apr 25, 2012 at 1:17 comment added TerronaBell Great -- thanks for the pointer; I'll take a look.
Apr 23, 2012 at 19:41 history answered Liviu Nicolaescu CC BY-SA 3.0