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Jan 23, 2013 at 16:06 answer added Robert Bryant timeline score: 11
Apr 23, 2012 at 16:01 vote accept Miranda Holmes-Cerfon
Apr 23, 2012 at 23:13
Apr 22, 2012 at 22:16 comment added Anton Petrunin @Ryan, tubular neighbourhood is not good here; in this case the equitation holds only on $M$, but not in a neighborhood.
Apr 22, 2012 at 22:12 answer added Anton Petrunin timeline score: 6
Apr 22, 2012 at 17:57 comment added Ryan Budney Yes, of course you can. This comes up in the differential-geometric proof of the tubular neighbourhood theorem, for example. You can write out them map fairly explicitly in terms of holonomy, or in your case using your gradient vectors.
Apr 22, 2012 at 15:46 comment added Yuchen Liu You can extend the normal vectors of $M$ in small scale and by inverse function theorem they do not intersect with others in a small neighborhood of $M$, which is isomorphic to a neighborhood of the zero section of the normal bundle of $M$.
Apr 22, 2012 at 15:29 history asked Miranda Holmes-Cerfon CC BY-SA 3.0