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Timeline for closed subset of weakly lindelof

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Apr 22, 2012 at 8:08 comment added KP Hart It can, spaces in which this happens are called H-closed: en.wikipedia.org/wiki/H-closed_space
Apr 21, 2012 at 20:04 comment added Douglas Somerset Many thanks. Tick to the first answer (by a minute). Looking at the (non-Hausdorff) examples which motivated this question, I now see that one of them has a non-weakly-Lindelof closed set whose complement is a dense open compact set. Thus the whole space is weakly Lindelof. In fact it has the stronger property that every open cover has a finite subfamily with dense union. Presumably this stronger property cannot occur in a non-compact Hausdorff space?
Apr 21, 2012 at 19:56 vote accept Douglas Somerset
Apr 21, 2012 at 18:18 history answered KP Hart CC BY-SA 3.0