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Apr 21, 2012 at 12:36 comment added Pietro Majer Also, a $k$-Lipschitz function $f$ on a subset $Y$ of a metric space $(X,d)$ has a cheap $k$-Lipschitz extension $$\tilde f(x):=\inf_{y\in Y} f(y)+kd(x,y)$$
Apr 21, 2012 at 9:18 vote accept Mike
Apr 21, 2012 at 9:10 comment added Piero D'Ancona If $f$ is Lipschitz on $\Gamma$, use a partition of unity to work locally, then use a Lipschitz continuous local change of variables to straighten the boundary, and you are reduced to the case $\Gamma$ is $x _n=0$. If you have a Lipschitz function on $x _n=0$ it is trivial to extend it to a Lipschitz function on the whole space (just take $F(x',x_n)=f(x')$).
Apr 21, 2012 at 8:28 comment added Mike Hi, so there exists an extension operator from the set of Lipschitz continuous functions on $\Gamma$ to $H^1(\Omega)$?
Apr 20, 2012 at 23:06 history answered Piero D'Ancona CC BY-SA 3.0