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Apr 20, 2012 at 19:32 comment added Bill Johnson Or: every separable Banach space embeds isometrically into $C[0,1]$, which clearly embeds isometrically into $L_\infty$.
Apr 20, 2012 at 19:30 comment added Bill Johnson Every separable Banach space is isometrically isomorphic to a quotient of $\ell_1$, hence every separable reflexive Banach space embeds isometrically into $\ell_\infty$, which in turn embeds isometrically into $L_\infty$.
Apr 20, 2012 at 19:27 comment added Igor Rivin Maybe I did (as you see I am not very with it;) In the alluded to discussion, the OP had asked for a family of functions with prescribed $2-$ and $1-$ norms, and with sup norm bounded by $1.$ As pointed out by @fedya, this last condition is the hard one (otherwise you construct a geodesic on the sphere in three dimensions and you are done), but the set of linear combinations of three given functions with sup norm $\leq 1$ appears to be an arbitrary convex centrally symmetric set (as you seem to confirm...) so...
Apr 20, 2012 at 19:24 comment added Igor Rivin That's what I thought. Why is that obvious?
Apr 20, 2012 at 19:24 comment added Bill Johnson Perhaps you meant to ask something slightly different?
Apr 20, 2012 at 19:23 history answered Bill Johnson CC BY-SA 3.0