Timeline for Fubini's theorem without completeness or $\sigma$-finiteness conditions
Current License: CC BY-SA 3.0
5 events
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| Jun 15, 2020 at 7:27 | history | edited | CommunityBot |
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| Nov 5, 2013 at 21:49 | comment | added | Giovanni | Anyway, if this is a counterexample or not depends on the definition of integrable: a function can be defined to be integrable in the extended sense if either $\int f^+ < \infty$ or $\int f^- < \infty$. In that case, the characteristic function of the diagonal is an honest integrable function (in the extended sense) and hence a counterexample to the statement, +1 indeed | |
| Apr 21, 2012 at 13:59 | comment | added | Adam Saltz | Ah! Thank you for pointing out my error, Makoto (and Pietro and Juan). | |
| Apr 19, 2012 at 5:06 | comment | added | Makoto Kato | Adam, the measure of the diagonal is not finite. So that's not a counterexample for my assertion. | |
| Apr 19, 2012 at 4:37 | history | answered | Adam Saltz | CC BY-SA 3.0 |