Timeline for Is the cap product bilinear?
Current License: CC BY-SA 3.0
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Apr 18, 2012 at 20:54 | comment | added | Mariano Suárez-Álvarez | math.stackechange.com would be a fine place to ask this, though! | |
Apr 18, 2012 at 20:44 | comment | added | Martin Brandenburg | Yes, this is linear extension. In more detail, for every cochain $\psi$ we have a map from $k$-simplices $\sigma$ to $k-l$ chains, and then extend this map to a homomorphism on the free abelian group on the $k$-simplices, i.e. the $k$-chains. So this is just the definining universal property of the free abelian group. These kind of definitions are abundant. However, please take a look at the FAQ of MO; you will find out that these "elementary" questions do not fit here. | |
Apr 18, 2012 at 19:56 | history | asked | Mr-Cups | CC BY-SA 3.0 |