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Nov 14, 2013 at 13:47 comment added Tomasz Kania Let me point out that ultraproducts of Banach spaces are never injective (unless finite-dimensional); see matematicas.unex.es/~fcabello/files/printable/66sub.pdf Theorem 6.1
Apr 20, 2012 at 15:34 comment added Bill Johnson ...the sum of any two totally incomparable closed subspaces of any Banach space is closed.
Apr 20, 2012 at 15:33 comment added Bill Johnson If $X$ is a subspace of $\ell_2 \oplus c_0$ that is isomorphic to $\ell_2$, then, since the projection onto $c_0$ is strictly singular when restricted to $X$, the projection onto $\ell_2$ is an isomorphism on some finite codimensional subspace of $X$. On the other hand, if $Y$ is subspace of $\ell_2 \oplus c_0$ that is isomorphic to $c_0$, then the projection onto $\ell_2$ is compact on $Y$. Play with these two facts to see that $X + Y$ is complemented (note that it is automatically closed by the two facts since e.g. the intersection of $X$ and $Y$ must be finite dimensional; in fact,...).
Apr 20, 2012 at 11:27 comment added Olaf Kummers A wonderful answer. Unfortunately, the above-mentioned property for $\ell_2\oplus c_0$ is not clear to me...
Apr 19, 2012 at 17:59 vote accept Olaf Kummers
Apr 18, 2012 at 18:24 history edited Bill Johnson CC BY-SA 3.0
Corrected typo.
Apr 18, 2012 at 15:10 history answered Bill Johnson CC BY-SA 3.0