Timeline for is f a polynomial provided that it is "partially" smooth?
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
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| Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
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| Apr 20, 2012 at 4:25 | history | edited | GH from MO | CC BY-SA 3.0 |
changed "dence" to "dense" at one instance
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| Apr 15, 2012 at 21:43 | comment | added | Terry Tao | At each stage, f_n is polynomial on some union of disjoint intervals. One picks a q = q_n outside of these intervals, then one can take I to be an interval around q which does not intersect any of the existing intervals. This way, f_{n+1} is polynomial on all the intervals that f_n was, plus an additional new interval containing q. | |
| Apr 15, 2012 at 21:23 | comment | added | Matthias Ludewig | Can you clarify your construction? What interval I do you use the lemma for? | |
| Apr 15, 2012 at 5:21 | comment | added | Ben | In fact,i create this question while think about the question mathoverflow.net/questions/34059/…. I proved the function $f$ locally a polynomial and wondered if I can use that property to solve that problem. | |
| Apr 15, 2012 at 2:51 | vote | accept | Ben | ||
| Apr 15, 2012 at 0:44 | history | answered | Terry Tao | CC BY-SA 3.0 |