Timeline for Why is the classifying space of the natural numbers homotopy equivalent to the circle?
Current License: CC BY-SA 3.0
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| Apr 21, 2012 at 4:34 | comment | added | Gao 2Man | Your first method is interesting. Most other answers show that $N{\mathbb{N}}\to N{\mathbb{Z}}$ is a weak equivalence. However, you show that a weak equivalence can be found in the other direction. That is, you identify an embedding of the simplicial circle $S^1\hookrightarrow N{\mathbb{N}}$ that is a weak equivalence. Thank you! | |
| Apr 18, 2012 at 6:54 | vote | accept | Gao 2Man | ||
| Apr 14, 2012 at 18:02 | history | edited | Tyler Lawson | CC BY-SA 3.0 |
deleted 2 characters in body; edited body; edited body
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| Apr 14, 2012 at 17:56 | history | answered | Tyler Lawson | CC BY-SA 3.0 |