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Apr 15, 2012 at 16:27 vote accept Damiano Lupi
Apr 15, 2012 at 8:58 comment added Sam Nead I swapped $A$ and $B$ in your question to match the usage in Minsky. That is, $A$ is a bound in $(S, \rho)$ while $B$ is a bound in $N$. (This means that $B$ should be replaced by $A$ in Misha's comment. Sorry Misha!)
Apr 15, 2012 at 8:55 history edited Sam Nead CC BY-SA 3.0
Swapped order of A, B to match Minsky
Apr 15, 2012 at 8:44 answer added Sam Nead timeline score: 1
Apr 14, 2012 at 23:20 comment added Misha Are you assuming a lower bound $\epsilon$ on injectivity radius of $N$? If you do then diameter of $g(S)$ is bounded above by some function $B$ of genus of the surface and $\epsilon$. Then you take your $B$ to be the function above.
Apr 14, 2012 at 15:25 comment added Dylan Thurston I fixed a typo in your transcription of Minsky's lemma (an inequality went the wrong way).
Apr 14, 2012 at 15:23 history edited Dylan Thurston CC BY-SA 3.0
Fixed a typo in lemma statement
Apr 14, 2012 at 14:50 history asked Damiano Lupi CC BY-SA 3.0