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Apr 15, 2012 at 23:19 comment added Benjamin Steinberg If F is the face poset of a simplicial complex, then it is straightforward to verify the order complex of F is the barycentric subdivision. A vertex of the order complex is an element f of F which corresponds to the barycenter of f. It is easy to check under this correspondence chains are simplices of the barycentric subdivision. Try it out on a 2-simplex.
Apr 15, 2012 at 16:51 comment added Simon Lentner GREAT, THANX, THAT HELPS! I've looked up "order complexes" and these indeed nice :-)...well, I didn't even fully "believe" I could just on/off central primitive idempotents, but embedding them into matrix rings certainly boosted my intuition (shame!) What is the argument/theory that descibes the complex then as a subdevided simplex?
Apr 15, 2012 at 16:50 vote accept Simon Lentner
Apr 12, 2012 at 13:17 history edited Benjamin Steinberg CC BY-SA 3.0
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Apr 12, 2012 at 12:47 history answered Benjamin Steinberg CC BY-SA 3.0