Timeline for Are algebraic groups defined by their invariants in tensor spaces?
Current License: CC BY-SA 3.0
3 events
| when toggle format | what | by | license | comment | |
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| Apr 14, 2012 at 19:28 | comment | added | SGP | Hi, I agree. Sorry about that. Paul's reference is right on target. | |
| Apr 11, 2012 at 11:47 | comment | added | Xandi Tuni | I do not think that this answers the question. In order to use loc.cit., one should be able to deduce from the conditions (1) and (2) that that the inclusion $G\subseteq H$ induces an equivalence of categories $\mathrm{Rep}(H)\to \mathrm{Rep}(G)$. | |
| Apr 11, 2012 at 11:21 | history | answered | SGP | CC BY-SA 3.0 |