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Apr 9, 2012 at 22:28 history edited Chris Gerig CC BY-SA 3.0
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Apr 9, 2012 at 22:27 comment added Chris Gerig Haha ooops. Well, nice redundancy then.
Apr 9, 2012 at 22:23 comment added Ryan Budney Aren't they essentially the same? Write $z \in S^1$ as $z = e^{i\theta}$ then $|z-1|^2 = 2-2Re(z) = 2-2\cos(\theta)$.
Apr 9, 2012 at 22:12 history answered Chris Gerig CC BY-SA 3.0