Timeline for Proving a messy inequality
Current License: CC BY-SA 3.0
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Apr 6, 2012 at 18:03 | comment | added | VSJ | The derivatives in $p$ and $q$ give me really complicated expressions so that their being non-zero is not at all obvious. You are right in that the maximum of the function along the boundary is zero, this can be evaluated. | |
Apr 6, 2012 at 16:39 | history | answered | Robert | CC BY-SA 3.0 |