Timeline for irreducible elements in a ideal of $R[x_1,x_2]$
Current License: CC BY-SA 3.0
8 events
when toggle format | what | by | license | comment | |
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Apr 8, 2012 at 16:25 | history | edited | Emil Jeřábek | CC BY-SA 3.0 |
Make the bounds tight. (You can interpolate $n$ points by a degree $n-1$ polynomial.)
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Apr 7, 2012 at 0:03 | comment | added | Will Sawin | @Daniel: Let $y,f(x)$ be as before and $g(x)$ vanish at the $x$ coordinates of the set of points, then $(y-f(x))^2+g(x)^2$ is irreducible in $\mathbb R[x,y]$, because it splits in $\mathbb C[x,y]$ into $(y-f(x)+ig(x))(y-f(x)-ig(x))$, neither of which is in $\mathbb R[x,y]$ | |
Apr 6, 2012 at 15:32 | comment | added | Daniel | @J.C. Ottem I have a question, how can I put in the coefficients the conditions of being irreducible? | |
Apr 6, 2012 at 15:31 | comment | added | Daniel | @Will Sawin Your polynomials has other roots right? ( Not just the finite points, What can I do to find a polynomial that only has that finite points and it´s also irreducible)? | |
Apr 6, 2012 at 7:15 | comment | added | Georges Elencwajg | I would never have thought there was such a beautifully elementary solution: congratulations, Will ! | |
Apr 6, 2012 at 5:46 | comment | added | Daniel | Ah and I forgot something, not only must cancel on this points, and be irreducible, also has only that roots , and no more! | |
Apr 6, 2012 at 2:39 | history | edited | Will Sawin | CC BY-SA 3.0 |
added 477 characters in body
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Apr 6, 2012 at 2:28 | history | answered | Will Sawin | CC BY-SA 3.0 |