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Jan 16, 2013 at 13:15 comment added Martin Brandenburg Somehow all my questions are still open ...
Apr 5, 2012 at 7:56 vote accept Martin Brandenburg
Apr 3, 2012 at 20:52 comment added Theo Johnson-Freyd My understanding is that set-theoretic difficulties come in when inverting a class of morphisms. For instance, inverting all topological maps which are identity on homotopy groups.
Apr 3, 2012 at 20:50 comment added Theo Johnson-Freyd @David: The point is that Martin is inverting precisely one morphism $f: x \to y$, for fixed $x,y$. Then if you also fix $z$, there is just a set of zig-zags of shape $y \overset{f^{-1}}\to x \to z$, namely the set $\hom(x,z)$. I agree that there is a class of possible $z$s, but the problem is not that $C_f$ has a class of objects, but whether for fixed objects $z,w$ is there a set of zig-zags connecting them.
Apr 3, 2012 at 16:50 comment added David White @Theo. I hope I'm not misreading your question. The way I normally think of it is that you can't apply the relations you want if the collection is not a set. The collection of all zigzags $z \rightarrow y \rightarrow x \rightarrow \dots \rightarrow w$ is not a set in general. For instance, if $C=Set$ then you have an entire class worth of zigzags just of the form $y\rightarrow x \rightarrow z$, since there should be a class worth of $z$ you can choose. Is this what you were asking?
Apr 3, 2012 at 14:31 history edited Martin Brandenburg CC BY-SA 3.0
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Apr 3, 2012 at 13:16 history edited Martin Brandenburg CC BY-SA 3.0
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Apr 3, 2012 at 12:40 history edited Martin Brandenburg CC BY-SA 3.0
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Apr 3, 2012 at 8:49 comment added Martin Brandenburg @Ralph: Weibel only talks about left+right multiplicative systems, and $\{f\}$ doesn't have this property. See also my comment after Question 1.
Apr 3, 2012 at 8:32 comment added Ralph Don't know if it helps, but there is a criterium in Weibel (Intr. Hom. Alg.) 10.3.6 which he calls "locally small multiplicative system".
Apr 3, 2012 at 8:23 comment added Martin Brandenburg @Theo: Hm, right. But doesn't this contradict Mike's comment?
Apr 3, 2012 at 8:16 history edited Martin Brandenburg CC BY-SA 3.0
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Apr 3, 2012 at 4:34 comment added Theo Johnson-Freyd On question 1: Maybe I'm being dumb. How can localizing at a single morphism $f:x\to y$ force you out of the universe? If $z,w$ are objects in $C_f$, a morphism $z\to w$ in $C_f$ is a word whose letters are composable morphisms in $C$ or $f^{-1}$, but modulo relations. After contracting all composable morphisms, you are left with a string of the form $z \to y \to x \to y \to x \to \dots \to x \to w$, where all of the $y \to x$ maps are $f^{-1}$ and all other maps are in $C$. For fixed $z,w$, it seems that there is just a set of these (if $C$ is locally small).
Apr 3, 2012 at 0:42 answer added Peter Arndt timeline score: 5
Apr 2, 2012 at 23:23 answer added David White timeline score: 4
Apr 2, 2012 at 23:01 history edited David White CC BY-SA 3.0
Fixed a typo, corrected name of a reference
Apr 2, 2012 at 21:44 comment added Mike Shulman I don't think there is a necessary and sufficient condition you can impose on C and f to ensure that the localization is locally small. Model categories are one technique for this; enriched notions of homotopy are another.
Apr 2, 2012 at 21:36 history asked Martin Brandenburg CC BY-SA 3.0