Timeline for Is reflexivity an open condition?
Current License: CC BY-SA 3.0
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| Apr 3, 2012 at 6:54 | comment | added | Olivier Benoist | @Sasha : It is part of the statement of Kollar's article (arXiv:0805.0576 Proposition 28 (3)), and it is proven there. By noetherian induction, you only need to show that it is constant on an open subset of $T$, hence, you will only have to show that it is "given by restrictions of one coherent sheaf to the fibers" on an open subset of $T$. | |
| Apr 3, 2012 at 2:46 | comment | added | Sasha | Olivier, how do you know that the polynomial $P(F_t^{\vee\vee})$ is constructible? The problem is that a priori $F_t^{\vee\vee}$ is just a collection of sheaves on the fibers, it is NOT given by restrictions of one coherent sheaf to the fibers... | |
| Apr 2, 2012 at 21:10 | vote | accept | jlk | ||
| Apr 2, 2012 at 20:49 | history | answered | Olivier Benoist | CC BY-SA 3.0 |