Timeline for A matrix diagonalization problem
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 4, 2012 at 19:24 | vote | accept | silvanmx | ||
| May 4, 2012 at 19:24 | |||||
| May 4, 2012 at 19:08 | comment | added | silvanmx | You are right! That solution gives actually a specific one for a given $X$. It seems Spenser's reasoning above answers the question. | |
| Apr 2, 2012 at 16:16 | comment | added | silvanmx | If $Y\ne X$, then $X^TWX = D(X^TX)^{-1}X^TY$ which is (I'm guessing) non-diagonal. | |
| Apr 2, 2012 at 15:55 | comment | added | Federico Poloni | Yes, but what about other possible values of $Y\neq X$ that would return a diagonal matrix $D_2\neq D$? | |
| Apr 2, 2012 at 15:51 | history | answered | silvanmx | CC BY-SA 3.0 |