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Apr 3, 2012 at 18:04 comment added domotorp Now you caught me! I guess I meant that picking any 2 vertices from any 2 classes, you can map them into any 2 other vertices of the respective classes with an automorphism, but your construction is a good counterexample even for this, so just forget my comment...
Apr 2, 2012 at 20:07 comment added Seva Sorry for my illiteracy, but what is "$2$-vertex-transitivity"?
Apr 2, 2012 at 13:37 comment added domotorp Indeed. I think instead of inefficient you wanted to write insufficient. Now I wonder if 2-vertex-transitivity, or in general r-1-vertex-transitivity is sufficient.
Apr 2, 2012 at 12:40 comment added Seva I appended an answer at the end of my original post.
Apr 2, 2012 at 7:12 comment added domotorp Oh, I have no noticed you ask for vertex transitive... I don't know anything about that for hypergraphs. For non-empty graphs with an even number of vertices you must have a perfect matching in this case, this follows from the Gallai-Edmonds Decomposition. Do you have a counterexample for hypergraphs?
Apr 2, 2012 at 7:09 history edited domotorp CC BY-SA 3.0
added first line
Mar 31, 2012 at 18:49 comment added Seva One more remark: there is no necessary and sufficient condition which is easy to check computationally. However, there still can possibly exist a "logically simple" and useful condition!
Mar 31, 2012 at 18:36 comment added Seva And, by the way: does the problems remain NP-complete if we confine to vertex-transitive hypergraphs?
Mar 31, 2012 at 18:31 comment added Seva Thanks! I was unaware of the three-dimensional matching problem. As to the second part of your answer, the degree assumptions are exactly what I had in mind mentioning "unreasonable conditions"...
Mar 31, 2012 at 14:10 history answered domotorp CC BY-SA 3.0