Skip to main content
5 events
when toggle format what by license comment
Apr 10, 2012 at 21:08 vote accept Naga Venkata
Mar 30, 2012 at 21:46 answer added Alain Valette timeline score: 3
Mar 30, 2012 at 19:07 comment added user20421 Take $\mathbb Z$ (discrete topology) as closed subgroup of $\mathbb R$, suppose $V$ is of dimension one over $F$, when $F$ is not "big enough", there are only trivial character of $Z$ to $F^{*}$ which could be extended to $\mathbb R$, e.g $F=\mathbb Q_p$.
Mar 30, 2012 at 18:43 comment added B R I haven't thought this all the way through, but many examples of non-normal abelian $G_1$ inside non-abelian $G_2$ give obstructions. For example, let $G_1$ be strictly upper-triangular matrices in $G_2=GL_2(\mathbb R)$. All irreducible representations of $G_1$ are $1$-dimensional, but the only $1$-dimensional representations of $G_2$ factor through the determinant, so are trivial on $G_1$. This depends on what you mean by "extending/restricting" and the result being "equal to" the original. For example, Frobenius reciprocity says that induction and restriction are adjoint functors.
Mar 30, 2012 at 18:09 history asked Naga Venkata CC BY-SA 3.0