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Apr 13, 2017 at 12:58 history edited CommunityBot
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Mar 30, 2012 at 20:05 comment added Balazs The $E$-poly involves a signed summation in the cohomology degree - so there can be cancellation. There is some non-$(p,p)$ stuff that cancels out.
Mar 30, 2012 at 12:22 comment added Dan Petersen I am confused about the example of Katz that you mention -- if the $E$-polynomial of $X$ is a function of $xy$, then how can $X$ have cohomology not of $(p,p)$ type?
Mar 30, 2012 at 9:47 vote accept Balazs
Mar 30, 2012 at 9:43 vote accept Balazs
Mar 30, 2012 at 9:45
Mar 30, 2012 at 9:03 answer added naf timeline score: 7
Mar 30, 2012 at 8:02 history asked Balazs CC BY-SA 3.0