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Apr 1, 2012 at 16:28 comment added Sasha Downvote me if I am wrong, but it seems that I don't need $E$ to have "functorial path objects for fibrant objects" as written above, but just "path objects for fibrant objects" (all the rest the same).
Mar 29, 2012 at 18:58 comment added Mike Shulman One useful criterion for (2) is that the right adjoint $G$ preserves (sufficiently highly) filtered colimits.
Mar 29, 2012 at 18:56 comment added Sasha Ah, I am sorry. You mean that $E$, which we still do not know to be a model category, should be shown to have functorial factorization, in order not to check (3).
Mar 29, 2012 at 16:54 comment added Sasha Thank you! So if I assume that my model categories come with functorial factorizations (triv cofib, fib) , (cofib, triv fib) I am OK with (3). What about (2), is there some easy general widely satisfied criterion for that?
Mar 29, 2012 at 16:49 vote accept Sasha
Mar 29, 2012 at 10:07 history answered Ittay Weiss CC BY-SA 3.0