Timeline for Degree of generators of irreducible components
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 29, 2012 at 13:53 | comment | added | Angelo | Dear Jérôme, of course I don't mind. | |
| Mar 29, 2012 at 13:17 | history | edited | Angelo | CC BY-SA 3.0 |
added 146 characters in body
|
| Mar 29, 2012 at 9:39 | comment | added | Jérôme Poineau | I would like to add that I am sorry I cannot accept your answer too. I chose Elkies' since it was a direct and concrete answer to my question (but I believe yours could also be made concrete). I hope you do not mind. Actually I like your answer a lot even if I was rather disappointed not to have found it myself, since this was really in my line of thoughts. Indeed, I was trying to find a counterexample by trying to find a curve of degree smaller than $d^2$ in $\mathbb{P}^3$ such that the space of surfaces of degree d is a line. And that is exactly what you did. Still a long way to go... | |
| Mar 29, 2012 at 6:29 | comment | added | Jérôme Poineau | Thank you for your answer. I guess $S_1$ refers to one of the general surfaces you choose at the beginning. | |
| Mar 29, 2012 at 3:45 | history | undeleted | Angelo | ||
| Mar 29, 2012 at 3:44 | history | edited | Angelo | CC BY-SA 3.0 |
added 28 characters in body; added 41 characters in body
|
| Mar 29, 2012 at 1:02 | history | deleted | Angelo | ||
| Mar 29, 2012 at 0:25 | comment | added | Angelo | To Noam: oops, sorry, of course you are right. | |
| Mar 28, 2012 at 23:51 | comment | added | Noam D. Elkies | But the component is not required to be a complete intersection of hypersurfaces of degree at most $d$. If $d=2$ then your construction gives a twisted cubic curve $C$, which is indeed cut out by quadrics, though of course not as a complete intersection. | |
| Mar 28, 2012 at 22:15 | history | answered | Angelo | CC BY-SA 3.0 |