Timeline for Quantum group Uq(sl(2))
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 26, 2012 at 23:26 | vote | accept | Ryan | ||
| Mar 26, 2012 at 23:26 | vote | accept | Ryan | ||
| Mar 26, 2012 at 23:26 | |||||
| Mar 25, 2012 at 22:30 | comment | added | Ryan | Yes, Adrien, you are absolutely correct. Sorry for the dumb question! I was caught up in the context and was not thinking very clearly. Thank you for your patience. | |
| Mar 24, 2012 at 18:28 | comment | added | Adrien | How do you define it otherwise ? This is the usual definition of $x^y$.. | |
| Mar 24, 2012 at 16:41 | comment | added | Ryan | In other words, is there a reason it is defined this way as opposed to something else? | |
| Mar 24, 2012 at 16:37 | comment | added | Ryan | Where does this definition come from? I've looked in several texts and none of them mention this definition for $q^{a}$. | |
| Mar 24, 2012 at 10:37 | comment | added | Adrien | $q^a$ is by definition $\exp(\log(q) a)=\sum (\log(q)a)^n/n!$. | |
| Mar 24, 2012 at 5:39 | comment | added | Ryan | Thank you Adrien for clarifying. If I may, I'm trying to fill in some background as I go. Where does the the assignment $q^{a} = \sum\frac{log(q)^{n}a^{n}}{n!}$ come from? | |
| Mar 24, 2012 at 3:01 | comment | added | Adrien | It's a direct computation, I edited my answer. | |
| Mar 24, 2012 at 2:57 | history | edited | Adrien | CC BY-SA 3.0 |
added 176 characters in body; added 71 characters in body
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| Mar 24, 2012 at 1:09 | comment | added | Ryan | Thanks for the reply. What's the best way to prove this? | |
| Mar 24, 2012 at 0:31 | history | answered | Adrien | CC BY-SA 3.0 |