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Mar 21, 2012 at 22:05 comment added Joel David Hamkins It was my pleasure. I like the question very much, and I think it is a great example to illustrate the point that failing to verify membership is not the same as verifying non-membership.
Mar 21, 2012 at 21:53 history edited Joel David Hamkins CC BY-SA 3.0
fixed typo
Mar 21, 2012 at 21:33 comment added Stefan.M Yes, you are right that my algorithm is wrong, it works only for languages which are both in P. Since P is in NP \cap coNP I thought that way is good but there are some catches. But the truth is there has to be completely another approach throught verifiers and certificates, that's quite obvious. Thank you once again for your explanation.
Mar 21, 2012 at 21:29 vote accept Stefan.M
Mar 21, 2012 at 20:11 history edited Joel David Hamkins CC BY-SA 3.0
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Mar 21, 2012 at 19:58 history edited Joel David Hamkins CC BY-SA 3.0
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Mar 21, 2012 at 19:52 history answered Joel David Hamkins CC BY-SA 3.0