Timeline for Surjectivity of Invariants
Current License: CC BY-SA 3.0
7 events
when toggle format | what | by | license | comment | |
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Mar 20, 2012 at 8:41 | vote | accept | mark | ||
Mar 20, 2012 at 1:47 | history | edited | Ralph | CC BY-SA 3.0 |
slight simplification
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Mar 20, 2012 at 1:45 | comment | added | Ralph | I don't know, if there is such a characterization ($W$ $k$-free is sufficient, probably also $W$ $k$-projective). And thanks for pointing out the correct order of the Reynolds operator. | |
Mar 19, 2012 at 19:44 | comment | added | Mark Wildon | @Ralph Your argument shows, still more generally, that if $U$ is a submodule of $V$ with quotient module $V/U \cong W$ then there is a $k$-algebra homomorphism $k[V] \rightarrow k[W]$ that preserves degrees and invariants. Is there any characterization of when the induced map $k[V]^G \rightarrow k[W]^G$ is surjective? (One small typo: the Reynolds averaging operator sends $k[V]^H$ to $k[V]^G$ for $H \le G$.) | |
Mar 19, 2012 at 15:50 | comment | added | Ralph | Added: $r$ is degree-preserving. For let $u,w$ be monomials such that $r(u \otimes w) \neq 0$. Then $\deg u = 0$ and $\deg r(u \otimes w) = \deg(u \cdot w) = \deg w = \deg w + \deg u = \deg(w \otimes u)$. | |
Mar 19, 2012 at 15:27 | history | edited | Ralph | CC BY-SA 3.0 |
added 13 characters in body
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Mar 19, 2012 at 15:20 | history | answered | Ralph | CC BY-SA 3.0 |