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May 6, 2022 at 12:24 answer added Guy Fsone timeline score: 2
Apr 13, 2017 at 12:58 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
Mar 22, 2016 at 22:23 vote accept Beni Bogosel
Mar 20, 2012 at 16:45 answer added Deane Yang timeline score: 3
Mar 20, 2012 at 16:12 answer added Malte timeline score: 1
Mar 20, 2012 at 10:11 comment added Pietro Majer Also, $\Omega:=\{ y > x^2\log|x| \} $ has $C^1$ boundary, and for $h > 0$ the maximal $\rho$ such that $(0,h)\in B_\rho\subset \Omega$ is $o(1)$ as $h\to 0$.
Mar 19, 2012 at 10:28 history edited Beni Bogosel CC BY-SA 3.0
added 159 characters in body
Mar 19, 2012 at 10:23 comment added fedja No. Consider the domain $y>x^2\sqrt{sin(1/x)^2+x^{100}}$ near 0 (in other words, make a sequence of "almost angles" flattened by some factor to ensure that you stay $C^1$ at the limiting point.
Mar 19, 2012 at 10:04 history asked Beni Bogosel CC BY-SA 3.0