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Jul 8, 2016 at 2:25 comment added Tito Piezas III The function you describe involve what we call Lagrange resolvents. The situation is a bit more complicated. For an eqn of odd prime degree $p$, you need a resolvent of degree $p-1$ with coefficients that are algebraic numbers of $(p-2)!$ deg. Thus, for $p=3$, you only get a quadratic resolvent. However, for $p=5$, you'll need to solve a $(5-2)!=3!=6$ deg eqn. For $p=7$ it is already $(7-2)!=5!=120$ deg eqn. And so on.
Feb 27, 2013 at 15:22 history edited Mathlover CC BY-SA 3.0
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Mar 19, 2012 at 9:41 history asked Mathlover CC BY-SA 3.0