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Mar 19, 2012 at 15:15 comment added Robert Bryant @Misha: You are welcome. Note, by the way, that this shows that the maximum dimension of such an $L$ is $1{+}m(n)$ where $m(n)$ is the largest integer such that $\mathbb{R}^n$ is a module over $Cl\bigl(m(n)\bigr)$. Thus, $m(n)$ is easy to determine when $n$ is given by consulting the classical theory of Clifford algebras. In particular $m(2k{+}1) = 0$, $m(4k{+}2)=1$, $m(8k{+}4)=3$, $m(16k{+}8)=7$, and $m(16k) = m(k)+8$.
Mar 18, 2012 at 18:43 history edited Robert Bryant CC BY-SA 3.0
fixed notation for clarity
Mar 18, 2012 at 18:25 history answered Robert Bryant CC BY-SA 3.0