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Mar 19, 2012 at 15:42 history edited Denis Serre CC BY-SA 3.0
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Mar 18, 2012 at 18:53 history edited Denis Serre CC BY-SA 3.0
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Mar 18, 2012 at 18:24 comment added Nikita Sidorov Denis, for $k = d -1$ one can take the companion matrix for $x^d-x^{d-1}-\dots-x-1$. This is a Pisot number (called the multinacci number), hence $k=d-1$.
Mar 18, 2012 at 17:42 comment added rpotrie Thanks, this is useful. I guess it should not be deleted, some key words are of importance, at least for me (in order to look into references is important to have those key words).
Mar 18, 2012 at 17:12 history answered Denis Serre CC BY-SA 3.0