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Mar 13, 2012 at 19:17 comment added Leonid Positselski Yes, I think one can: if X is an end-acyclic complex, P is a bounded above complex of projectives, and P -> X is a quasi-isomorphism, setting C to be the cone of the latter and arguing as above, one only needs the complexes Hom(P,C) and Hom(C,X) to be acyclic for the argument to hold. As H^*(Hom(P,P)) = H*(Hom(P,X)) = D(X,X[]) = Hot(X,X[]) = H^*(Hom(X,X)), this seems to be true.
Mar 13, 2012 at 18:23 vote accept Jan Weidner
Mar 13, 2012 at 18:23 comment added Jan Weidner Thank you for your explanation! Do you know, if one could take more generally instead of a projective/injective resolution an end-acyclic resolution in order to compute the $A_\infty$ structure? Here a complex X is called end-acyclic, if its shifted endomorphisms in the homotopy category and in the derived category coincide: Hot(X,X[n])=D(X,X[n]) for all n
Mar 12, 2012 at 19:29 history edited Leonid Positselski CC BY-SA 3.0
fixed grammar ("of" and "the" inserted)
Mar 12, 2012 at 19:12 history answered Leonid Positselski CC BY-SA 3.0