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Mar 12, 2012 at 1:29 comment added Allen Knutson Got it. $\ \ \ $
Mar 11, 2012 at 16:53 comment added Liviu Nicolaescu In the real case the multiplicity is zero. To see this look at the equation $x^2-\varepsilon=0$. For $\varepsilon>0$ it has two solutions, one counter with multiplicity $1$ and the other with multiplicity $-1$ and thus the intersection number of the graph of $x^2-\varepsilon$ with the $x$-axis is zero. If $\varepsilon <0$, then the equation has no solution, and the above intersection number is also zero.
Mar 11, 2012 at 14:23 comment added Allen Knutson Multiplicity 0? Not 2?
Mar 9, 2012 at 14:33 history answered Liviu Nicolaescu CC BY-SA 3.0