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Mar 22, 2012 at 4:26 comment added Misha Yes, but the construction is not very explicit. All I could tell you is that the manifold will have dimension $\le 6$ (you can get it down to $4$ if Eilenberg-Ganea conjecture holds for this group).
Mar 21, 2012 at 16:26 comment added yeshengkui That's interesting. Do you mean for the rationals $Q$ we can find a manifold whose fundamental group is $Q$?
Mar 11, 2012 at 23:44 comment added Misha Igor Belegradek has found a very nice modern reference for Whitehead's result on the last page of math.cornell.edu/~hatcher/AT/AT-exercises.pdf This is given as an exercise with a hint and the proof (via a mapping telescope) is much easier and nicer than the original one.
Mar 9, 2012 at 2:00 comment added Misha The proof I gave is well-known (among topologists) provided that $G$ admits $K(G,1)$ which is a finite CW-complex. The only tricky issue in general is to get local finiteness for which the only reference I know is the original Whitehead's paper. Does somebody know a modern reference?
Mar 9, 2012 at 1:46 comment added Misha Hausdorff, 2nd countable, locally homeomorphic to ${\mathbb R}^n$.
Mar 9, 2012 at 1:37 comment added Greg Friedman What do you mean by "(textbook) topological manifold"?
Mar 8, 2012 at 21:07 vote accept berl13
Mar 8, 2012 at 19:20 history answered Misha CC BY-SA 3.0