Skip to main content
Removed comment re waiting period.
Source Link
Joseph O'Rourke
  • 150.9k
  • 36
  • 358
  • 958

Here is YangMills's answer, so I can accept it (after a several-day waiting period enforced by the software):

The class $\cal{R}^*$ of surfaces considered by Zelditch excludes all Zoll surfaces of revolution, because of the "simple length spectrum" hypothesis (page 2) which is never satisfied for Zoll surfaces of revolution. For example it implies that the length $2L$ of "meridian" geodesics cannot be equal to the length of all other geodesics, while in the Zoll case all geodesics have the same length.

Here is YangMills's answer, so I can accept it (after a several-day waiting period enforced by the software):

The class $\cal{R}^*$ of surfaces considered by Zelditch excludes all Zoll surfaces of revolution, because of the "simple length spectrum" hypothesis (page 2) which is never satisfied for Zoll surfaces of revolution. For example it implies that the length $2L$ of "meridian" geodesics cannot be equal to the length of all other geodesics, while in the Zoll case all geodesics have the same length.

Here is YangMills's answer, so I can accept it:

The class $\cal{R}^*$ of surfaces considered by Zelditch excludes all Zoll surfaces of revolution, because of the "simple length spectrum" hypothesis (page 2) which is never satisfied for Zoll surfaces of revolution. For example it implies that the length $2L$ of "meridian" geodesics cannot be equal to the length of all other geodesics, while in the Zoll case all geodesics have the same length.

Post Made Community Wiki
Source Link
Joseph O'Rourke
  • 150.9k
  • 36
  • 358
  • 958

Here is YangMills's answer, so I can accept it (after a several-day waiting period enforced by the software):

The class $\cal{R}^*$ of surfaces considered by Zelditch excludes all Zoll surfaces of revolution, because of the "simple length spectrum" hypothesis (page 2) which is never satisfied for Zoll surfaces of revolution. For example it implies that the length $2L$ of "meridian" geodesics cannot be equal to the length of all other geodesics, while in the Zoll case all geodesics have the same length.