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Mar 8, 2012 at 8:05 history edited J.C. Ottem CC BY-SA 3.0
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Mar 8, 2012 at 4:39 comment added Karl Schwede I believe there is no map from one to the other. In the example J.C. Ottem gives, the blow up of $(x^2,y)$ can be obtained as follows. Blow up $(x,y)$, then blow up another point on that first blowup (the origin on one of the usual charts), and then contract the first exceptional curve. There's no map between $Bl_{(x^2,y)}X$ and $Bl_(x,y) X$, at least no map over $X$.$$\text{ }$$ Just because you have an inclusion of Rees algebras, does not mean that there is an everywhere defined map of the blow-ups. In the given example, one of the points of the overring contracts to an irrelevant ideal.
Mar 7, 2012 at 21:34 history edited J.C. Ottem CC BY-SA 3.0
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Mar 7, 2012 at 21:25 comment added gio Thanks for the example. But at least, there is a natural map from one to another?
Mar 7, 2012 at 20:28 history edited J.C. Ottem CC BY-SA 3.0
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Mar 7, 2012 at 20:15 history edited J.C. Ottem CC BY-SA 3.0
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Mar 7, 2012 at 19:48 history answered J.C. Ottem CC BY-SA 3.0