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Mar 7, 2012 at 21:38 comment added Julien Melleray @Alexander: Todor speaks about the strong operator topology. Finite-dimensional perturbations of identity are dense because a basic open set only "names" finitely many vectors. Anyway, as he proved in the paper he links to, continuity assumptions can be dropped when one considers representations on a separable space.
Mar 7, 2012 at 21:19 vote accept Michał Oszmaniec
Mar 7, 2012 at 21:19 history bounty ended Michał Oszmaniec
Mar 7, 2012 at 15:22 comment added Alexander Chervov @Todor why dense ? In what topology ? direct limit - operators of the form 1+K , K - finite-dim. you cannot approximate $e^{ia} Id$ by this operators if we speak about norm-topology.
Mar 5, 2012 at 9:09 comment added Todor Tsankov I should have also mentioned that the direct limit of the finite-dimensional groups is dense in $U(\mathcal{H})$.
Mar 4, 2012 at 18:34 comment added Alexander Chervov @Todor But restriction and extension does not mean equvivalence of irreps. I mean when you restrict irrep you can get reducible, as well as, when you extend non-equiv. irreps. you can get equiv reps. As far as I remember it is always emphasized that the two groups: 1) U(H) and 2) limit U(n) has very different rep. theory. – Alexander Chervov
Mar 4, 2012 at 16:35 history edited Todor Tsankov CC BY-SA 3.0
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Mar 4, 2012 at 16:19 comment added Todor Tsankov I am not sure I understand your comment. Every representation of the infinite-dimensional unitary group restricts to a representation of the direct limit of finite-dimenssional unitary groups and conversely, each of the representations they consider extends to one of the full unitary group.
Mar 4, 2012 at 13:47 comment added Anatoly Kochubei Meanwhile, indeed, for the subgroup considered by Kirillov, there is a relation of the requested kind.
Mar 4, 2012 at 13:34 comment added Anatoly Kochubei As I wrote in my answer, the paper you cite are not about the whole unitary group. As for the results, see the quotation from Olhanski himself in my answer.
Mar 4, 2012 at 13:20 history answered Todor Tsankov CC BY-SA 3.0