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S Dec 2, 2023 at 10:21 history suggested The Amplitwist CC BY-SA 4.0
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S Dec 2, 2023 at 10:21
Mar 5, 2012 at 15:49 vote accept darij grinberg
Mar 5, 2012 at 8:54 answer added Vladimir Dotsenko timeline score: 1
Mar 4, 2012 at 17:02 answer added Vladimir Dotsenko timeline score: 1
Mar 4, 2012 at 15:08 comment added darij grinberg Yes. It is the linear independence that I don't understand.
Mar 4, 2012 at 12:33 comment added Theo Johnson-Freyd So that I understand the question, the point is that $\Omega_p$ is an odd-degree form if $p$ is odd (and already $0$ if $p$ is even), and so there cannot be any terms of form $\Omega_p \wedge \Omega_p = -\Omega_p \wedge\Omega_p$. So it follows that your sequences are a spanning set, and the only thing missing is the independence? Put another way, the question is why the ring of invariants is a polynomial algebra (on odd variables) and not a quotient thereof?
Mar 4, 2012 at 3:20 history asked darij grinberg CC BY-SA 3.0