Skip to main content
14 events
when toggle format what by license comment
Apr 13, 2017 at 12:58 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
Jul 31, 2015 at 3:33 comment added Boaz Tsaban @AsafKaragila I believe that such questions (as do essentially all of mathematics outside set theory) assume AC implicitly.
Mar 1, 2012 at 5:08 history edited CommunityBot
insert duplicate link
Mar 1, 2012 at 5:08 history closed Steven Gubkin
Theo Johnson-Freyd
Andreas Blass
Emil Jeřábek
Ryan Budney
exact duplicate
Feb 29, 2012 at 18:10 comment added Emil Jeřábek (Arturo’s and Steven’s examples are one and the same.)
Feb 29, 2012 at 17:02 comment added Asaf Karagila @Arturo: Indeed if you take $\bigoplus_X\mathbb Z$ then $X$ indeed embeds into it as you said. However without the axiom of choice it is possible that the group generated by this embedding has a strictly larger cardinality.
Feb 29, 2012 at 16:56 comment added Arturo Magidin P.S. I believe that you only need the axiom of choice in order to prove that the resulting group is bijectable to $X$ (and thus use transfer of structure to endow $X$ with an abelian group structure); the fact that the group exists given a set $X$, and that you can embed $X$ into the group (via mapping $x\in X$ to the characteristic function of $\{x\}$), does not seem to me to require AC, but if I'm wrong I'm sure the experts on this will correct me.
Feb 29, 2012 at 16:43 comment added Arturo Magidin You can take the direct sum of $|X|$ copies of $\mathbb{Z}$ (assuming the axiom of choice, at any rate). This is the set of all functions $f\colon X\to\mathbb{Z}$ of finite support, with pointwise addition. The cardinality is $|X|$.
Feb 29, 2012 at 16:34 vote accept Chris Heunen
Feb 29, 2012 at 16:29 comment added Asaf Karagila You can read several answers on math.SE: math.stackexchange.com/q/105433/622
Feb 29, 2012 at 16:20 answer added Joel David Hamkins timeline score: 14
Feb 29, 2012 at 16:19 comment added Steven Gubkin The free abelian group on an infinite set X has the same cardinality as X
Feb 29, 2012 at 16:16 comment added Joel David Hamkins See related question mathoverflow.net/questions/12973/…, concerning the use of the axiom of choice in imposing a group structure.
Feb 29, 2012 at 16:12 history asked Chris Heunen CC BY-SA 3.0