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May 22, 2020 at 17:24 comment added LSpice @LaurentBerger's reference: Sanyal, Sottile, and Sturmfels - Orbitopes.
Nov 10, 2016 at 5:06 comment added YCor A few basic remarks: (a) the set of extremal points of the convex hull of $SO_n$ is exactly $SO_n$ (idem for $O^-_n$); (b) for $n$ even these sets are symmetric; (c) for all $n\ge 2$ the convex hull of $SO_n$ and $O^-_n$ have 0 in their intersection, as we see looking just at the convex hull of diagonal $\pm 1$-matrices (d) for $n\ge 3$ the convex hull of $SO_n$ and $O^-_n$ have nonempty interior (hence their intersection is a neighborhood of 0). (This is because it contains 0 and using [I skip details] that the representation in $\mathbf{R}^n$ is absolutely irreducible for $n\ge 3$.)
Nov 10, 2016 at 4:33 history edited YCor
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Nov 9, 2016 at 17:33 vote accept Denis Serre
Nov 9, 2016 at 15:58 answer added Suvrit timeline score: 11
Feb 29, 2012 at 15:47 comment added Denis Serre Merci, Laurent !
Feb 29, 2012 at 15:31 comment added Laurent Berger The answer for $n=3$ is given in $\S 4.1$ of arxiv.org/abs/0911.5436. In $\S 4.4$ of ibid, there's a discussion of some properties of the convex hull of $SO(n)$ for larger $n$.
Feb 29, 2012 at 9:02 history edited Denis Serre CC BY-SA 3.0
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Feb 29, 2012 at 8:47 history edited Denis Serre CC BY-SA 3.0
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Feb 29, 2012 at 8:44 comment added Yemon Choi Ricky, it is customary in many places/books/texts/whatever in analysis to use the word "contraction" to mean "distance non-increasing". This is how almost all practising operator theorists and most functional analysts I've met use the word, for instance
Feb 29, 2012 at 8:44 comment added user5810 If $B$ is open, then $B$ has no extremal points, and so is not the convex hull of the set of its extremal points. $\hspace{.2 in}$ If $B$ is closed, then $B$ has members that are not contractions. $\;\;$
Feb 29, 2012 at 8:20 history asked Denis Serre CC BY-SA 3.0