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Feb 29, 2012 at 17:42 answer added Olivier Benoist timeline score: 12
Feb 29, 2012 at 5:46 comment added Angelo When you contract curves, the resulting morphism is not finite.
Feb 28, 2012 at 23:18 vote accept anon
Feb 28, 2012 at 23:10 answer added Karl Schwede timeline score: 12
Feb 28, 2012 at 23:01 comment added Will Sawin No. One classic example of a non-projective 3-fold involves contracting a bunch of rational curves in a projective 3-fold. This gives a finite morphism $X\to Y$, with $X$ projective. Since $Y$ is complete but not projective, it is not quasi-projective. I'll see if I can dig it up.
Feb 28, 2012 at 22:49 history asked anon CC BY-SA 3.0