Timeline for relation between Ass Ext(M,N) and Ass M ,Ass N
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| S Mar 29, 2015 at 7:36 | history | suggested | user 1 | CC BY-SA 3.0 |
format edition
|
| Mar 29, 2015 at 6:55 | review | Suggested edits | |||
| S Mar 29, 2015 at 7:36 | |||||
| Oct 6, 2013 at 13:50 | comment | added | user40948 | Please, I want to know the proof of the fact AssHomR(M,N)=SuppM∩AssN if M,N are finitely generated R modules given R is noetherian. | |
| Mar 8, 2012 at 17:14 | vote | accept | Stella | ||
| Mar 3, 2012 at 21:22 | comment | added | Neil Epstein | Actually there's something stronger true than what you say in the last line. Namely, if $R$ is any commutative ring, $M$ is a finitely presented module, and $N$ is any module, then $Ass Hom_R(M,N) = Supp M \cap Ass N$. This is indeed well-known. For instance, it appears as an exercise in the book by Bruns and Herzog. | |
| Feb 29, 2012 at 4:22 | answer | added | Hailong Dao | timeline score: 5 | |
| Feb 29, 2012 at 3:09 | comment | added | Hailong Dao | This is probably not a homework question. | |
| Feb 29, 2012 at 1:38 | history | edited | Benjamin Steinberg | CC BY-SA 3.0 |
Format; deleted 2 characters in body
|
| Feb 28, 2012 at 20:56 | comment | added | Stella | You would really think about me. | |
| Feb 28, 2012 at 20:49 | history | edited | Stella | CC BY-SA 3.0 |
added 138 characters in body; added 9 characters in body
|
| Feb 28, 2012 at 15:06 | comment | added | Vladimir Dotsenko | It would be most helpful if you give some motivation and/or background. The way it phrased now makes it look like you want us to do your homework... | |
| Feb 28, 2012 at 9:07 | history | asked | Stella | CC BY-SA 3.0 |