Timeline for Explicit expression for multivariable meromorphic series
Current License: CC BY-SA 3.0
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| Feb 28, 2012 at 16:59 | comment | added | Abhishek Parab | Yes, you can assume an embedding. For every permutation on $m$ symbols, you have an ordering of $\mathbb Z^m$ and you may assume that $K((X,Y))$ is contained in the field of functions from $\mathbb Z^m$ to $K$ with well-ordered support under this ordering. | |
| Feb 28, 2012 at 5:54 | comment | added | S. Carnahan♦ | I don't have a complete answer, but one typically does not have a unique series expression without imposing additional constraints. For example one may embed $K((X,Y))$ in either $K((X))((Y))$ or $K((Y))((X))$ by expanding quotients with one term order or another. This yields different series expressions of $1/(X-Y)$. | |
| Feb 28, 2012 at 3:36 | history | asked | Abhishek Parab | CC BY-SA 3.0 |