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Jun 22, 2021 at 4:09 history edited YCor CC BY-SA 4.0
added tag, removed capitals (the question was bumped anyway)
S Jun 22, 2021 at 3:30 history suggested ABIM CC BY-SA 4.0
Made title a bit more clear and to the point :)
Jun 21, 2021 at 19:09 review Suggested edits
S Jun 22, 2021 at 3:30
Jun 21, 2021 at 19:06 answer added ABIM timeline score: 2
Mar 16, 2012 at 8:08 vote accept Tomas
Mar 15, 2012 at 20:33 comment added Jason Swanson The formula $P(X_t=k\mid Y_t=i)=\pi_k(i)$ can be reformulated as $P(X_t=k\mid Y_t)=\pi_k(Y_t)$, and this formula makes perfectly good sense, no matter what the distribution of $Y_t$. See en.wikipedia.org/wiki/Conditional_expectation#Formal_definition and en.wikipedia.org/wiki/….
Mar 15, 2012 at 14:05 answer added Joris Bierkens timeline score: 3
Feb 29, 2012 at 9:44 comment added Tomas @ Stéphane Laurent Could recommend some literature (papers) on this the conditional stochastic processes topic. Because all I can find is just short notes in textbooks and no deeper analysis. I would be greatfull for it.
Feb 28, 2012 at 15:36 comment added Stéphane Laurent It is easy to extend: for each $t$ there is a conditional law of $X_t$ given $Y_t$.
Feb 28, 2012 at 13:02 history edited Tomas CC BY-SA 3.0
added 5 characters in body
Feb 27, 2012 at 17:34 history asked Tomas CC BY-SA 3.0