Timeline for The role of the mean value theorem (MVT) in first-year calculus
Current License: CC BY-SA 3.0
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| Feb 28, 2012 at 4:57 | comment | added | KConrad | Why do you need to bring in MVT in this discussion for a first-year calculus class? All you need to know for comparing different solutions of $y' = f(x)$, once the linearity of differentiation is known, is that the solutions to $y' = 0$ -- on an interval -- are precisely the constant functions. To students this conclusion will be intuitively obvious when they think about the geometric meaning of $y' = 0$. So this doesn't seem like a compelling rationale for presenting MVT. | |
| Feb 27, 2012 at 19:13 | history | edited | Lee Mosher | CC BY-SA 3.0 |
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| Feb 27, 2012 at 15:00 | history | answered | Lee Mosher | CC BY-SA 3.0 |